On Grundy Total Domination Number in Product Graphs

A longest sequence (v1, . . ., vk) of vertices of a graph G is a Grundy total dominating sequence of G if for all i, N(υj)\∪j=1i-1N(υj)≠∅N({\upsilon _j})\backslash \bigcup\nolimits_{j = 1}^{i - 1} {N({\upsilon _j})} \ne \emptyset . The length k of the sequence is called the Grundy total domination...

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Main Authors: Brešar Boštjan, Bujtás Csilla, Gologranc Tanja, Klavžar Sandi, Košmrlj Gašper, Marc Tilen, Patkós Balázs, Tuza Zsolt, vizer Máté
Format: Article
Language:English
Published: Sciendo 2021-02-01
Series:Discussiones Mathematicae Graph Theory
Subjects:
Online Access:https://doi.org/10.7151/dmgt.2184
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Summary:A longest sequence (v1, . . ., vk) of vertices of a graph G is a Grundy total dominating sequence of G if for all i, N(υj)\∪j=1i-1N(υj)≠∅N({\upsilon _j})\backslash \bigcup\nolimits_{j = 1}^{i - 1} {N({\upsilon _j})} \ne \emptyset . The length k of the sequence is called the Grundy total domination number of G and denoted γgrt(G)\gamma _{gr}^t(G) . In this paper, the Grundy total domination number is studied on four standard graph products. For the direct product we show that γgrt(G×H)≥γgrt(G)γgrt(H)\gamma _{gr}^t(G \times H) \ge \gamma _{gr}^t(G)\gamma _{gr}^t(H) , conjecture that the equality always holds, and prove the conjecture in several special cases. For the lexicographic product we express γgrt(G∘H)\gamma _{gr}^t(G \circ H) in terms of related invariant of the factors and find some explicit formulas for it. For the strong product, lower bounds on γgrt(G⊠H)\gamma _{gr}^t(G \boxtimes H) are proved as well as upper bounds for products of paths and cycles. For the Cartesian product we prove lower and upper bounds on the Grundy total domination number when factors are paths or cycles.
ISSN:2083-5892