On roman domination number of functigraph and its complement
Let $$G = (V(G),E(G))$$ be a graph and $$f:V(G) \to \{ 0,1,2\} $$ be a function where for every vertex $$v \in V(G)$$ with $$f(v) = 0,$$ there is a vertex $$u \in {N_G}(v),$$ where $$f(u) = 2.$$ Then $$f$$ is a Roman dominating function or a $$RDF$$ of $$G.$$ The weight of $$f$$ is $$f(V(G)) = \sum\...
| Main Authors: | , |
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| Format: | Article |
| Language: | English |
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Taylor & Francis Group
2020-01-01
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| Series: | Cogent Mathematics & Statistics |
| Subjects: | |
| Online Access: | http://dx.doi.org/10.1080/25742558.2020.1858560 |