Lucas numbers of the form PX2, where P is prime
Let Ln denote the nth Lucas number, where n is a natural number. Using elementary techniques, we find all solutions of the equation: Ln=px2 where p is prime and p<1000.
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| Format: | Article |
| Language: | English |
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Hindawi Limited
1991-01-01
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| Series: | International Journal of Mathematics and Mathematical Sciences |
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| Online Access: | http://dx.doi.org/10.1155/S0161171291000935 |